Re: [Boost-users] [lambda] Variable assignment from lambda expression

From: jarvi (jarvi_at_[hidden])
Date: 2005-09-26 10:40:35

the var function makes a lambda functor out of a variable, so you can 
write the expression as:

var(n) = _1

Best, Jaakko

On Sep 26, 2005, at 9:13 AM, Alexander Borghgraef wrote:

> Hi all,
>
>   I have been trying out boost::lambda for the first time, and I did 
> encounter something which I can't seem to solve.
>  Simplified, what I'd like to do amounts to this:
>
>  list<int> intlist;  // fill up list someway
>  int n;
>  for_each( intlist.begin(),
>                 intlist.end(),
>                 n = _1
>               );
>
>   Obviously, this fails because it implies a cast from placeholder to 
> int, which isn't defined. Is there some way to do
>  this using lambda?
>
> -- 
> Alex Borghgraef_______________________________________________
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