Re: [Boost-users] How to select the name of class definition instead ofvariable name in XML archive

From: Robert Ramey (ramey_at_[hidden])
Date: 2005-10-22 19:39:36

People have asked this before, its really needed, but as far as anyone knows, there is no portable way to do this.   Depending on your needs type_id might return a string you can use.

Robert Ramey
  "Piyush Kapadia" <piyush.kapadia_at_[hidden]> wrote in message news:435aa424.08d6201b.180b.68ff_at_mx.gmail.com...
  In following code - archive results in tag name as T as T is used in BOOST_SERIALIZATION_NVP(T) statement.

  Instead I want actual type name for T, instead of just T as Tag name, how to achieve this ???

   

   

  template<class T>

  void Serialize(const char * filename)

  {

              std::ofstream ofs(filename);

              assert(ofs.good());

              boost::archive::xml_oarchive oa(ofs);      

              oa << BOOST_SERIALIZATION_NVP(T);

              ofs.close();

  }

   

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