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From: Pavol Droba (droba_at_[hidden])
Date: 2005-12-23 13:04:08
Hi,
You might be able to do it using the string_algo find_iterator.
#include <boost/algorithm/string.hpp>
using namespace std;
using namespace boost;
...
typedef find_iterator<string::iterator> string_find_iterator;
string_find_iterator It=make_find_iterator(str1, token_finder(is_space()));
for(int i=0; i<maxi; i++)
for(int j=0; j<maxj; j++)
{
if(It!=string_find_iterator())
{
v[i][j]=*It;
}
else
{
break;
}
}
Regards,
Pavol
On Fri, Dec 23, 2005 at 07:30:48PM +0200, Alex Vinokur wrote:
> Can the boost Tokenizer package split a string into into a series of
> serieses of tokens (a vector of vectors of tokens)?
>
> ====================
> For instance,
> string s = "ab cd \nxy z\n123";
>
> vector<vector<string> > v;
>
> Output should be as follows:
> v[0][0] = "ab";
> v[0][1] = "cd";
>
> v[1][0] = "xy";
> v[1][1] = "z";
>
> v[2][0] = "123";
> ====================
>
> http://boost.org/libs/tokenizer/introduc.htm doesn't contain such a
> sample.
>
> Alex Vinokur
> email: alex DOT vinokur AT gmail DOT com
> http://mathforum.org/library/view/10978.html
> http://sourceforge.net/users/alexvn
>
>
>
>
>
>
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