Re: [Boost-users] How to bind the first of a pair?

From: yinglcs2_at_[hidden]
Date: 2006-02-22 20:17:06

Thanks. I would like to  use your suggestion (since it
is simpler/cleaner).

however, you said 'you just need to
 proceed from the iterator 
 lower_bound returns until you hit an element with
 .first != x (or end()). '

How can I find the element with .first != x?

I try using end(), but it does not work. it copies
evething from (.fires == x) to the end of the list.

--- Peter Dimov <pdimov_at_[hidden]> wrote:

> yinglcs2_at_[hidden] wrote:
> 
> > I am not sure how low_bound()  will work.
> > My understanding is it only return the ** first **
> > instance.
> 
> But so does find_if.
> 
> > but I am looking for ** all instances ** which fit
> the
> > condition (i.e. the first value of the key pair
> > matches the input parameter).
> 
> Since a map is sorted by its key, you just need to
> proceed from the iterator 
> lower_bound returns until you hit an element with
> .first != x (or end()). 
> Anyway, ...
> 
> >>> iterator& itr = find_if(myMap.begin(),
> 
> ... you need to omit the reference here.
> 
> iterator itr = find_if( ... 
> 
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>
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> 

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