Re: [Boost-users] Using boost::lambda::bind with std::transform

From: Kobi Cohen-Arazi (kobi.cohenarazi_at_[hidden])
Date: 2006-04-27 10:47:33

Hi Sebastian,

Hmmm...... I think I know what the problem is ...
Foo::get is const

struct Foo{
   std::string get() const { ... }
};

So it is not a good candidate to use in string::replace.
I wonder how I can work around it, since I want to transform a _copy_ of
that.
Is there a way to create a copy on the fly? something like:
...bind(rep, std::string(bind(&Foo::get, _1)), 0, 5, ""));

Thanks again for your insights.
Kobi.

On 4/27/06, Sebastian Redl <sebastian.redl_at_[hidden]> wrote:
>
> Kobi Cohen-Arazi wrote:
>
> > Hi,
> >
> > I've tried that, and I got a bunch of errors. I'm using boost::bind
> > for that, not boost::lambda.
> > Here is the error
> >
> > The following line:
> > std::transform(array.begin(), array.end(), std::back_inserter(tr),
> >   bind(&std::string::replace, bind(&Foo::get, _1), 0, 5, ""));
> >
> > generates:
> > error: no matching function for call to 'bind(<unknown type>,
> > boost::_bi::bind_t<const std::string&, boost::_mfi::cmf0<const
> > std::string&, Foo>, boost::_bi::list1<boost::arg<1> > >, int,
> > uint32_t&, const char [1])'
>
> Hmmm ... the <unknown type> is suspicious. The problem might be that
> &std::string::replace is ambiguous, as it is overloaded. Try this:
>
> std::string & (std::string::*rep)(std::string::size_type,
> std::string::size_type, const char *) = &std::string::replace;
> std::transform(array.begin(), array.end(), std::back_inserter(tr),
>   bind(rep, bind(&Foo::get, _1), 0, 5, ""));
>
> Sebastian Redl
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