[Boost-users] [Random] newbie question on saving the generator state through stream operators

From: Marco Baldi (m.baldi_at_[hidden])
Date: 2006-09-04 11:59:29

Hello,

I have found another post on the subject, but it seems that no response
has followed (maybe the answer is so obvious...).
http://thread.gmane.org/gmane.comp.lib.boost.user/3901/focus=3901

However, even in http://www.boost.org/libs/random/random_demo.cpp
it is suggested to "Try boost::mt19937 or boost::ecuyer1988 instead of
boost::minstd_rand", but the following code (taken from the same file)
seems to work only when "generator" is of type boost::minstd_rand.

     // You can save the generator state for future use.  You can read the
     // state back in at any later time using operator>>.
     std::ofstream file("rng.saved", std::ofstream::trunc);
     file << generator;

I'm using bcb and get the following compiler error message when
"generator" is not of type boost::minstd_rand (but is boost::mt19937,
for example):
"'operator<<' not implemented in type '_STL::ofstream' for arguments
of type 'boost::mt19937'".

Any help would be appreciated,

thanks in advance,
Marco

-- 
No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.1.405 / Virus Database: 268.11.7/436 - Release Date: 01/09/2006