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From: Chris Weed (chrisweed_at_[hidden])
Date: 2006-10-19 08:59:26
Yes,
That clears up my understanding.
Thanks,
Chris
On 10/19/06, Peter Dimov <pdimov_at_[hidden]> wrote:
> Chris Weed wrote:
> > Hi,
> > I can get the following code to compile and it prints
> > 3 2
> > 5
> > but I don't quite understand why it doesn't print
> > 2 3
> > 5
> > or how to get it to do so. I thought since it is binding 2 to _1, this
> > would bind it to the a argument.
>
> Calling bind( fx, _1, 2 ) with 3 will put the '3' in the _1 and pass the 2
> intact, the result is fx( 3, 2 ). bind( fx, _1, _1 ) will call fx( 3, 3 ).
> bind( fx, 2, _1 ) calls fx( 2, 3 ). bind( fx, 4, 5 ) calls fx( 4, 5 ).
>
> Does it make sense now? bind is not an interpreter with a mini-language
> ("bind the second argument to 2"), you just pass the argument values, and _1
> is substituted with the first input argument (3 in your case).
>
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