Re: [Boost-users] Implementation of Exponential Distribution

From: Arnaldur Gylfason (arnaldur.gylfason_at_[hidden])
Date: 2006-10-23 11:34:40

>The second, more critical point: The implementation does not seem to be 
the
>correct inverse of the original function. Boost's implementation (with 
above
>modification) is:
>                -result_type(1) / _lambda * log(eng());

>But should actually be:
>                -log(eng()) / _lamda;

The expressions are the same because of operator associativiy. (i.e. x/y*z 
= (x/y)*z )

I believe you are right about the first point though.

cheers

Arnaldur