Re: [Boost-users] compiling only regex library

From: John Maddock (john_at_[hidden])
Date: 2006-12-16 04:45:24

I.B. wrote:
>> Hi ,
>>
>>
>> i want to  use boost regex++ for my project but dont want to compile
>> all boost libraries for now,
>> so i compiled using option:
>> --with-regex
>>
>> got no errors, and result library:
>> boost_regex-gcc-1_33_1.a
>>
>> copied all boost_<version>/boost headers to $HOME/include
>>
>> directory is like this:
>> $HOME/include/boost/regex.hpp
>>
>> have a simple test.cpp file that uses:
>>
>> boost::regex_search(...)
>>
>> i compiled like this:
>> g++  -o trun test.cpp -I/home/ig3/include -L/home/ig3/lib
>> -lboost_regex-gcc-1_33_1
>>
>>
>> got following error:
>>
>> test.cpp: In function `int main(int, char**)':
>> test.cpp:26: no matching function for call to `regex_search(
>>   __gnu_cxx::__normal_iterator<const char*, std::basic_string<char,
>>   std::char_traits<char>, std::allocator<char> > >&,
>>   __gnu_cxx::__normal_iterator<char*, std::basic_string<char,
>>   std::char_traits<char>, std::allocator<char> > >, boost::cmatch&,
>>   boost::regex&)'
>>
>> i wonder why is that. Thought iterator is a template that shouldnt be
>> compiled. Headers should be enough.

You've mixed your iterators up: you are passing std::string::iterator's to 
the function, but using boost::cmatch to accept the result (cmatch expects a 
const char* and *not* a string::iterator).  Use boost::smatch to accept the 
result instead.

Note: with some std lib's, std::string::iterator happens to be the type 
const char* and your code would compile.  You can not rely on this in 
general though.

HTH,

John.