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From: Ovanes Markarian (om_boost_at_[hidden])
Date: 2007-01-10 16:18:28


Ahh, sorry I also forget to mention, to make linear derivation as you wish,
you must always produce a unique type, which is ensured with the pair_c
construct.

Otherwise you get the following simplified scenario:

template <class T>
struct DataField {
     T data;
};

class SomeClass : public DataField<int>, DataField<int>, DataField<int>
{
        ...
};

 
In such a case compiler will produce a warning, which states that it will
only derive once from DataField<int>.

With Kind Regards,
Ovanes

-----Original Message-----
From: Ovanes Markarian [mailto:om_boost_at_[hidden]]
Sent: Wednesday, January 10, 2007 9:30 PM
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] [boost.mpl] Implementing a numeric index access
to fields of a composite class created with mpl::inherit_linearly

Hi!

you could use an mpl::pair type to produce a static mapping of int value to
type:

mpl::pair<mpl::int_<0>, int>

This is a little bit ugly, to write such a big construct, so you can write
the following construct

template<int N, class T>
struct pair_c : mpl::pair<mpl::int_<N>, T> {};

Actually pair_c could be your DataField struct, so you can add the T
instance to it:

template<int N, class T>
struct pair_c : mpl::pair<mpl::int_<N>, T> {
   T dataField;
};

Now you can define a vector of pair types as follows:
mpl::vector<pair_c<0, int>, pair_c<1, int>, pair_c<2, int> > my_vector;

we use in this sample pair_c to make any type unique, dependent on the
position in the vector.

The next step would be to define the class with linear inheritance:

template<class Seq>
struct linear_inherited :
        boost::mpl::inherit_linearly
        <
                Seq
        , boost::mpl::inherit<boost::mpl::_1, boost::mpl::_2>
>::type
{};

But now you would need the access function. I suggest to integrate this
function as a linear_inherited member:

template<class Seq>
struct linear_inherited :
        boost::mpl::inherit_linearly
        <
                Seq
        , boost::mpl::inherit<boost::mpl::_1, boost::mpl::_2>
>::type
{
        template<long N>
        typename boost::mpl::at_c<Seq, N>::type::second& nth_field()
        {
                typedef typename boost::mpl::at_c<Seq, N>::type* ptr_type;
                ptr_type ptr = static_cast<ptr_type>(this);
                return ptr->dataField;
        }

};

When this function is a member you save some effor on passing the sequence
type to its specialization, otherwise it will not know which type is meant.

Let me explain this function:

mpl has the at metafunction, which can access the Nth element of a static
vector. Here this function is used to calculate the result_type (in our case
it is always int, but we want to be generic ;), so you can make pair_c<0,
double>, pair_c<1, SomeStruct> etc.). The at metafunction returns the type
which was in the vector at this position, in our case this type is pair_c.
Now we need to access the field type T. mpl::pair is defined as template
<class X, class Y> struct pair {
   typedef X first;
   typedef Y second;
};

so, the type of our datafield in pair_c is of type second. Therefore the
function nth_field returns reference to second.

In the function itself we use the static_cast operator to calculate the
offset to our datafield within the class. And then we return the the field
contained there.

Below is the full listing I used to test and compile the scenario:

linear_inh_test.h
---------- START -------------------

#ifndef __OM_LINEAR_INHERITANCE_TEST_H__ #define
__OM_LINEAR_INHERITANCE_TEST_H__

#include <boost/mpl/at.hpp>
#include <boost/mpl/int.hpp>
#include <boost/mpl/pair.hpp>
#include <boost/mpl/lambda.hpp>
#include <boost/mpl/inherit.hpp>
#include <boost/mpl/identity.hpp>
#include <boost/mpl/placeholders.hpp>
#include <boost/mpl/inherit_linearly.hpp>

template<int N, class T>
struct pair_c : boost::mpl::pair<boost::mpl::int_<N>, T> {
        T dataField;
};

template<class Seq>
struct linear_inherited :
        boost::mpl::inherit_linearly
        <
                Seq
        , boost::mpl::inherit<boost::mpl::_1, boost::mpl::_2>
>::type
{
        template<long N>
        typename boost::mpl::at_c<Seq, N>::type::second& nth_field()
        {
                typedef typename boost::mpl::at_c<Seq, N>::type* ptr_type;
                ptr_type ptr = static_cast<ptr_type>(this);
                return ptr->dataField;
        }

};

#endif

__________ END ___________________

main.cpp
---------- START -------------------

#include "linear_inh_test.h"

#include <cassert>
#include <boost/mpl/vector.hpp>

int main()
{
        using namespace boost;
        typedef mpl::vector<pair_c<0, int>, pair_c<1, int>, pair_c<2, int> >
my_vector;

        linear_inherited<my_vector> test_instance;

        int& ref0 = test_instance.nth_field<0>();
        ref0 = 0;

        int& ref1 = test_instance.nth_field<1>();
        ref1 = 1;

        int& ref2 = test_instance.nth_field<2>();
        ref2 = 2;

        assert(
                        test_instance.nth_field<0>()
                  != test_instance.nth_field<1>()
                  != test_instance.nth_field<2>()
                  );

        return 0;
}

__________ END ___________________

With Kind Regards,

Ovanes Markarian

On Tue, January 9, 2007 21:51, Khalil Shalish wrote:
> Hello,
>
> I created the following composite class using mpl::inherit_linearly:
>
> template <class T>
> struct DataField {
> T data;
> }
>
> typedef mpl::inherit_linearly<
> mpl::vector< int, int, int>
> mpl::inherit< DataField<_2>, _1 >
>> Int3Composite;
>
> Int3Composite int3comp;
>
> Since the type of each data field is an int, I cannot use the type of
> the field to access the
data in the field.
>
> Q: Is there a way to write a template (call it get_field) to access
> the data using numeric
position in the type sequence. Something like this:
>
> int field_0 = get_field<0>(in3comp); //This returns the first int data
> field. int field_1 =
get_field<1>(int3comp);
>
> I am very new to C++ template programming and any help on this will be
very much appreciated.
>
> Thank you,
> Khalil Shalish
> kshalish_at_[hidden]
> _______________________________________________
> Boost-users mailing list
> Boost-users_at_[hidden]
> http://lists.boost.org/mailman/listinfo.cgi/boost-users
>

With Kind Regards,

Ovanes
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