Re: [Boost-users] split_iterator<string::iterator> example

From: Pavol Droba (droba_at_[hidden])
Date: 2007-02-20 15:18:38

Meryl Silverburgh wrote:
> On 2/20/07, Pavol Droba <droba_at_[hidden]> wrote:
>> Hi,
>>
>> There is realy no magic there. You just need to realize, that you
>> are not getting a string, rather a range. Range is a generalization of a
>> pair of iterators.
>>
>> In case of split_iterator, these iterators point to first and one past
>> the last character of the current token.
>>
>> Example can be found in
>> /boost/libs/algorithm/string/example/split_example.cpp
>>
>> Regards,
>> Pavol.
> 
> 
> Thanks for your help. I have another question, how can I can i
> terminate the for loop when loop using string_split?
> 
> class integer_compare {
> public:
>        bool operator() (const string_split::value_type &a, const
> string_split::value_type &b) {
> 	        // how can I iterate thru the string?  how can i terminate
> the for loop?
> 
> 		for (const string_split sitr = a; sitr != ???; sitr++) {
> 			
>                         // print out each substring (after '/' is stripped out)
> 			cout << copy_range<std::string>(*sitr) << endl;
> 			
> 		}
>                return true;
>        }
> };
> 
> 
> 

First of all, I don't understand your example. string_split::value_type 
is definitely not another split_iterator. it's type is (as I have 
mentioned in some previous mail) iterator_range<string::iterator>.

As for the loop termination, default-initialized split_iterator (i.e. 
string_split) functions as a terminator. Alternatively you can check the 
eof() method.

Regards,
Pavol.