Re: [Boost-users] [enable_if] using enable_if to extendstd::numeric_limits?

From: Ovanes Markarian (om_boost_at_[hidden])
Date: 2007-03-07 11:42:59

Hi!

I think you need to derive your class from enable_if< is_decimal_type<T> >.
If your compiler supports SFINAE and is_decimal_type<T>::value is false_
template will be derived from void which is not legal...

Best Regards,
Ovanes

-----Original Message-----
From: james.jones_at_[hidden] [mailto:james.jones_at_[hidden]]

Sent: Mittwoch, 7. März 2007 17:21
To: boost-users_at_[hidden]
Subject: [Boost-users] [enable_if] using enable_if to
extendstd::numeric_limits?

Suppose I have a set of templates that have a common interface (each is a
model of the same concept, to use that lingo). I'd like to extend
std::numeric_limits to support this concept. I'm trying to find a way to use
enable_if to do this, but I don't see how. Is this possible? Is there some
other trick to doing this?

Example with code (not real code):

template< class U, class V >
class model1;

tempalte< class U, class V >
class model2;

template< class U > 
is_decimal_type	{ static const bool value = false; };

template< class U, class V >
is_decimal_type < model1<U, V> >	{ static const bool value = true; };

template< class U, class V >
is_decimal_type < model2<U, V> >	{ static const bool value = true; };

Would like to do this:

template< class T >
class numeric_limits< T >
{
        // extensions go here
};

But only if is_decimal_type<T>::value is true (so that the partial
specialization only applies to my concept).

Thanks,
-
James Jones             Administrative Data Mgmt.
Webmaster               375 Raritan Center Pkwy, Suite A
Data Architect          Edison, NJ 08837
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