Re: [Boost-users] [boost::function] problem with void type as argument type

From: Seweryn Habdank-Wojewódzki (habdank_at_[hidden])
Date: 2007-03-26 16:28:03

Hi!

Douglas Gregor wrote:

>> Thanks for reply. However still I do not know how to proceed in that
>> case, because functions can not be partially specialized. Is there any
>> opportunity to prepare more less such a function which will automatically
>> detects arguments of boost::function template?
> 
> You can write multiple overloads of your "test" function, each of which
> accepts boost::function instances with a different number of function
> arguments:
> 
>   template<typename R>
>   void test (boost::function<T(void)>& f);
> 
>   template<typename R, typename T1>
>   void test (boost::function<T(T1)>& f);
> 
>   template<typename R, typename T1, typename T2>
>   void test (boost::function<T(T1, T2)>& f);
> 
>   template<typename R, typename T1, typename T2, typename T3>
>   void test (boost::function<T(T1, T2, T3)>& f);
> 
> Tedious, unfortunately, but it works.

Ok. It is long, but good enough.

Thanks and kind regards.

-- 
|\/\/|   Seweryn Habdank-Wojewódzki
 \/\/