[Boost-users] Question withdrawn

From: Marcin Kalicinski (kalita_at_[hidden])
Date: 2007-07-08 10:30:26

I withdraw the question.

def f():
    c = FindComponent("a")

c will actually have methods of ComponentA, for some reason this did not 
seem to work for me for the first time, but now it does.

sorry,
Marcin

> This may potentially be unrelated to Boost.Python, but how to do an 
> equivalent of C++ dynamic_cast in Python, having all the classes wrapped 
> using boost.python? See below:
>
> // All the components inherit from Component
> class Component { };
> class ComponentA: public Component { };
> class ComponentB: public Component { };
>
> // Find a component by name
> Component *FindComponent(const char *name);
>
> // In C++ result of FindComponent may be dynamic_casted to appropriate 
> type:
> void f()
> {
>    Component *c = FindComponent("a");
>    ComponentA *a = dynamic_cast<ComponentA *>(c);
> }
>
> How to do this in Python (all Component classes are wrapped)?
>
> def f():
>    c = FindComponent("a")
>    # Unforunately Python sees c as an instance of Component, not as 
> ComponentA which it really is
>    a = ???
>
> Thanks,
> Marcin