[Boost-users] Re : extract url with boost::regex

From: hallouina-ml_at_[hidden]
Date: 2007-11-26 12:07:21

No, I don't see this example, I was reading the documentation and example about regex iterator and not regex token iterator. I search on other website but don't find this example. I will study it.

Thanks John for always anwsering, and always fast answering. I was completly discouraged. Thanks again!



----- Message d'origine ----
De : John Maddock <john_at_[hidden]>
À : boost-users_at_[hidden]
Envoyé le : Lundi, 26 Novembre 2007, 17h50mn 31s
Objet : Re: [Boost-users] extract url with boost::regex

hallouina-ml_at_[hidden] wrote:
> Hello;
>
> I try to extract an url from a webpage and it's almostly done but
> completly unoptimised :
>
> Before I try with a regex iterator. But I don't understand the
> documentation.

:-(

Did you see this 
example:http://www.boost.org/libs/regex/example/snippets/regex_token_iterator_eg_2.cpp

It does exactly what you want - it exacts all the URL's from a HTML
 file.

>   boost::regex rexp(".*(http:\\/\\/.+)\"*.*");
>
>
> and I get this result :
>
> http://www.nolife-tv.com/"
> http://www.nolife-tv.com">
> http://www.nolife-tv.com/images/stories/noiz/1.jpg"
>
 http://www.nolife-tv.com/component/option,com_poll/task,results/id,16/Itemid,47/';"
> http://www.joomla.org"
> http://www.google-analytics.com/urchin.js"
> http://www.omniture.com
>
> and so on...
>
> I will cut and get only the url without the " or '
> why this regex get the " with it? I put the close bracket before the
> " so why?  I already try to do \\" rather than \"

Because the .* on the end of the expression will match whatever text
 follows 
the ", the grouping construct (...) spits out a *sub-expression* which
 you 
can access via the match_results::operator[] or match_results::str(i) 
methods.

HTH, John.

[...]




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