Re: [Boost-users] How to expose self defined type in boost.python

From: David Abrahams (dave_at_[hidden])
Date: 2008-01-31 23:12:35

on Mon Jan 14 2008, "Huang You Gong" <huangyougong-AT-gmail.com> wrote:

> Hi,
>  
> I try to use boost.python to invoke C++ library in Python, so I need to expose
> types and classes.
> Here is the c++ head file:
>  
> typedef int XTYPE;
> class XCLASS
> {
> public:
>         XTYPE getvalue( void ){ return XTYPE( 3 ); }
> };
>        
> So I write exposing code in BOOST_PYTHON_MODULE like this:
>  
> BOOST_PYTHON_MODULE( x )
> {
>         class_< XCLASS >( "XCLASS" )
>                 .def( "getvalue", &XCLASS::getvalue, return_value_policy<
> copy_non_const_reference >() )
>         ;
> }
>  
> but there is compiling error as using of undefined type.

The return_value_policy is wrong.  The type returned by getvalue is not
a reference type.

> what shall I do to make the type XTYPE known by boost.python?
> Thanks in advance!

Boost.Python already knows about int.

-- 
Dave Abrahams
Boost Consulting
http://boost-consulting.com