Re: [Boost-users] variant cast operators?

From: Jiri Palecek (jpalecek_at_[hidden])
Date: 2008-03-28 10:48:49

On Mon, 17 Mar 2008 20:05:58 -0000, Daniel Oberhoff  
<daniel_at_[hidden]> wrote:

> Hi,
>
> I am playing with boost::variant to introduce a more elegant property
> system into my current project. I was wondering why there are no cast
> operatorst defined for the variant types, to avoid having to type get<>:
>
> boost::variant<double,int,string> v;
> string s = v;
>
> is there a basic reason why this is not possible?

I guess it's because it's pretty dangerous to do implicit casts that may  
fail.

Regards
   Jiri Palecek