Re: [Boost-users] [boost][lexical_cast] simple example doesn't work with vector<T>

From: Andy Stevenson (andy.stevenson_at_[hidden])
Date: 2008-04-07 15:26:20

All,

Thanks to Steven Watanabe, Ovanes Markarian, Scott Murray, Alexander Nasonov
who all responded to this.

The suggestions were to put it into namespace std or boost, both seem to
work by the way.

However what is actually right here? Extending std seems distinctly non-std
!

Andy

-----Original Message-----
From: boost-users-bounces_at_[hidden]
[mailto:boost-users-bounces_at_[hidden]] On Behalf Of Steven Watanabe
Sent: 07 April 2008 20:04
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] [boost][lexical_cast] simple example doesn't work
with vector<T>

AMDG

Ovanes Markarian wrote:
> Just an addition:
>
> Explicit specialization of std templates is legal. So if you _exactly_ 
> know vector types for which your <<-operator should work you can write:
>
> namespace std
> {
>   template<>
>   ostream& operator<< (ostream& os, const vector<MyTypeX>& v)
>   {
>     copy(v.begin(), v.end(), ostream_iterator<T>(os, ";"));
>     return os;
>   }
> }
>
> By the way there was a big discussion about this on std list and I 
> fluently read the upcoming Standard draft and saw that this paragraph 
> changed. I not any longer sure if this will be allowed with the new 
> standard.

There has to be template to specialize.  The std library doesn't have an
overload of operator<< that matches std vector.  Specialization can't change
that.

In Christ,
Steven Watanabe

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