Re: [Boost-users] [function] template deduction issues

From: Steven Watanabe (watanabesj_at_[hidden])
Date: 2008-04-25 17:09:47

AMDG

Robert Dailey wrote:
> Say I have a function as follows:
>
> *template< typename t_packet >
> void Subscribe( boost::function<void (t_packet const&)> func )
> {
>     // gSignal is a boost::signal somewhere. Assume valid.
>     gSignal.connect( func );
> }*
>
> And in some other function, I invoke Subscribe() as follows:
> *
> void MyCallback( WalkPacket const& p )
> {
> }
>
> void MainTest()
> {
>     Subscribe( &MyCallback );
> }*
>
> The code above will actually not compile, since the template parameter 
> t_packet cannot be deduced. Is there a way I can make the template 
> deduction work?

You can construct a boost::function at the call site explicitly rather
than relying on the implicit conversion.

Alternately you can provide an overload of Subscribe for function pointers.

In Christ,
Steven Watanabe