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From: Sohail Somani (sohail_at_[hidden])
Date: 2008-05-22 13:28:34


Robert Ramey wrote:
> This can't work.
>
> load a pointer creates a new pointer with a copy of the original object.
>
> adding the following to your test should make this clear
>
> ...
> std::cout << "ref: " << *m.ref << std::endl;
> ...
> std::cout << "ref: " << *m2.ref << std::endl;
>

Ok, the author will know more than I! For the OP, you can have a map of
pointers which will work.

-- 
Sohail Somani
http://uint32t.blogspot.com

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