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From: Christoph (christoph.duelli_at_[hidden])
Date: 2008-05-30 14:15:32

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In reply to: Dave Jenkins: "Re: [Boost-users] [xpressive] first try: error handling, nested refs"

Dave Jenkins wrote:

> It works if you change the parenthesis:
>
> [ (ref(result) [ref(res_name)]) [s1] = s2 ];
It does. Thank you!

Christoph

Next message: Rupert Bruce: "Re: [Boost-users] [multi_array] how to modify the dimension of an array?"
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