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From: John Moeller (fishcorn_at_[hidden])
Date: 2008-06-17 13:08:22
John Moeller <fishcorn <at> gmail.com> writes:
>
> Hello all,
>
> I am trying to make an "is_range" metafunction that (essentially) returns
> mpl::true_ when the template parameter is a range (as defined by the
> boost::range library).
>
> I can do this if I create a specialization for every "non-range" type currently
> specialized by the library (such as built-in arrays, char strings, etc.).
> However, I'd like to have is_range work for a user-defined range without the
> user *also* needing to specialize is_range.
>
> I tried something like this:
>
> //////////////////////////////////////////////////////////////////////
> BOOST_MPL_HAS_XXX_TRAIT_DEF(type)
>
> template < bool B >
> struct is_range_impl
> : boost::mpl::false_
> {};
>
> template <>
> struct is_range_impl< true >
> : boost::mpl::true_
> {};
>
> template < typename R >
> struct is_range
> : is_range_impl< has_type< boost::range_iterator< R > >::value >
> {};
> //////////////////////////////////////////////////////////////////////
>
> Which does fine if R is a range (even when you use the non-intrinsic method of
> defining a custom class as a range), but if R is *not* a range, the compiler
> complains that "iterator" is not a member of the class that I'm passing as the
> parameter, because it defaults to using the embedded "iterator" type in the
> parameter.
>
> Is there a better way to define is_range so that it will work? I imagine that
> I'd have to use SFINAE somehow, but I can't quite see how to put it together.
>
> Many thanks ahead of time,
>
> --
>
> John Moeller
>
I figured out how to do it (and it's pretty simple):
template < typename R, typename V = void >
struct is_range_impl
: boost::mpl::false_
{};
template < typename R >
struct is_range_impl< R, boost::range_iterator< R > >
: boost::mpl::true_
{};
template < typename R >
struct is_range
: is_range_impl< R >
{};
Feel free to pick this apart; I wouldn't mind if it were made better.
Thanks,
-- John Moeller
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