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From: gast128 (gast128_at_[hidden])
Date: 2008-07-28 17:09:37
Andrej van der Zee <mavdzee <at> yahoo.co.uk> writes:
> #include <boost/exception/exception.hpp>
>
> namespace speedo {
>
> typedef boost::error_info<struct tag_error, unsigned> error_info;
>
> class __declspec(dllexport) exception : public boost::exception
> {
> };
>
> }
>
> When I try to compile this, I get the following warning:
>
> c:\cygwin\home\andrej\speedo\trunk\util\exception.h(14) : warning C4275: non
dll-interface class
> 'boost::exception' used as base for dll-interface class 'speedo::exception'
> C:\cygwin\home\Andrej\speedo\trunk\boost/exception/exception.hpp
(47) : see declaration of 'boost::exception'
> c:\cygwin\home\andrej\speedo\trunk\util\exception.h(13) : see
declaration of 'speedo::exception'
>
> Is this a problem, and, how do I get rid of this without changing the boost-
exception lib itself?
The exported attribute indicates that all functions from the class are
exported. The warning is that you can potentially call a non exported function
from the base class, e.g.:
struct public Base
{
void Foo1(); //impl. in cpp
};
struct __declspec(dllexport) Derived : public Base
{
void Foo2(); //impl. in cpp
};
void Foo()
{
Derived d;
d.Foo1(); //error, but at least a linker error
d.Foo2();
}
wkr,
me
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