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Subject: Re: [Boost-users] Comparing two vectors element by element
From: Sean Farrow (sean.farrow_at_[hidden])
Date: 2008-09-10 09:41:46
That is now what I have, chers.
Sean.
-----Original Message-----
From: boost-users-bounces_at_[hidden]
[mailto:boost-users-bounces_at_[hidden]] On Behalf Of Gevorg
Voskanyan
Sent: 10 September 2008 14:02
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] Comparing two vectors element by element
Sean Farrow wrote:
> It's not allower, the sizes aren't identical.
> Sean.
Then I think you can perfectly use the function below:
bool bitset_vector_less( const std::vector< std::bitset< 6 > > & lhs,
const std::vector< std::bitset< 6 > >
& rhs )
{
assert( lhs.size() == rhs.size() );
return std::equal( lhs.begin(), lhs.end(), rhs.begin(), BitSetComp()
);
}
where BitSetComp is the predicate you have shown earlier.
HTH,
Gevorg
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