Re: [Boost-users] [STL] Is there a std::abs<>() function?

Subject: Re: [Boost-users] [STL] Is there a std::abs<>() function?
From: Max (loadcom_at_[hidden])
Date: 2008-12-23 19:34:28

Hello Anteru,

Yes, there exist several overloads of abs() functions or similar
but some of them with different name, say fabs, fabsf, etc.
This make it impossible to use it in generic code.

More specifically, I've ever written this code

cout << std::abs<int>(-1) << endl;

but, to my very surprise, I get 0!

I have
#include <cmath>
#include <cstdlib>

I'm using VS2003SP1 under WinXP_SP1

Thanks
B/Rgds

Max




----- Original Message -----
From: Anteru 
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] [STL] Is there a std::abs<>() function?
Date: 2008-12-23 19:00:56

Max schrieb:
> Hello,
> 
> It's strange to me that there seems not to be a  std::abs<>() function
> in STL, with it I can write code like this:
> 
> double d = std::abs(-1.0);
> int i = std::abs(-1);
> 

> Does anybody else have the same feeling?

#include 

double d = std::abs (-1.0);

cmath pulls the standard math functions into the std namespace, and adds
a few overloads.

See for example:

http://www.dinkumware.com/manuals/?manual=compleat&page=math.html#abs


Cheers,
  Anteru

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