Re: [Boost-users] behavior conditional on template argument

Subject: Re: [Boost-users] behavior conditional on template argument
From: Matthieu Brucher (matthieu.brucher_at_[hidden])
Date: 2009-01-21 05:28:30

Hi,

You can use enable_if to let the compiler decide which one it should
instantiate. And the argument will be a custom defined type trait. I
think there are facilities to automatically define it on the presence
of a type, there may be soemthing for fucntions as well, but I don't
remember where they live (MPL ?)

Matthieu

2009/1/21 Hicham Mouline <hicham_at_[hidden]>:
> Hello,
>
> I have a template function
>
>
> template <typename M>
> void f(const M&)
> {
>  // call M.f1()
>  // call M.f2()
>
>  // some Ms have a function f1Andf2() which does f1()+ f2() work faster
>  // how can I write code that runs f1Andf2() if it's there
>  // otherwise runs f1() then f2()
> }
>
> regards,
> _______________________________________________
> Boost-users mailing list
> Boost-users_at_[hidden]
> http://lists.boost.org/mailman/listinfo.cgi/boost-users
>

-- 
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