Re: [Boost-users] [serialization] removing excess XML tags

Subject: Re: [Boost-users] [serialization] removing excess XML tags
From: Robert Ramey (ramey_at_[hidden])
Date: 2009-02-05 15:47:27

Make your own archive derived from xml_?archive.

Robert Ramey
  "Paul Heil" <paul.heil_at_[hidden]> wrote in message news:2fc4ff370902051118v6b811275rdad4dd46c04d40c9_at_mail.gmail.com...
  I'd like to use the boost::serialization library to generate XML that must be read by a third party application. Unfortunately, this application does not like the extra stuff that the serialization library generates.

  The code below generates XML that looks like this:
      <?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
      <!DOCTYPE boost_serialization>
      <boost_serialization signature="serialization::archive" version="5">
      <MYTAG class_id="0" tracking_level="0" version="0"></MYTAG>
      </boost_serialization>

  What I need is XML that looks more like this:
      <?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
      <MYTAG></MYTAG>

  What can I do to eliminate the extra stuff?

  Thanks,
  PaulH

  class MyClass
  {
  private:
      friend class boost::serialization::access;

      template<class Archive>
      void serialize(Archive &ar, const unsigned int version){};

  public:
      MyClass(){};
      friend std::ostream & operator<<(std::ostream &os, const MyClass &gp);
      virtual ~MyClass(){};
  };

  int main( int argc, _TCHAR* argv[] )
  { 
      MyClass mc;

      std::ofstream ofs("MyFile.xml");
      boost::archive::xml_oarchive oa(ofs);
      oa << boost::serialization::make_nvp( "MYTAG", mc );

      return 0;
  }

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