Re: [Boost-users] [result_of] member function

Subject: Re: [Boost-users] [result_of] member function
From: er (erwann.rogard_at_[hidden])
Date: 2009-02-28 21:02:12

Steven Watanabe wrote:
> AMDG
> 
> er wrote:
>> Is this feasible? How?
>>
>>     class Foo
>>     {
>>         template<typename Signature>
>>         struct result{};
>>
>>         template<typename F>
>>         struct result<(F::*f)(value_type)>{
>>             typedef
>>         value0_type if f == foo,
>>             value1_type if f == bar           type;
>>         };
>>
>>     value0_type foo(value_type);
>>     value1_type bar(value_type);
>>
>>     };
>>
>> How do I invoke result_of to get the result type of F::foo(value_type)?
> 
> This is not what boost::result_of is for.
> 
> In Christ,
> Steven Watanabe
Thak you for your answer. I was probably misinterpreting the part that reads

The implementation permits the type F to be a function pointer, function 
reference, member function pointer, or class type.

in the doc of result_of. Is someone aware of an example that illustrates 
the "member function pointer" part?