Re: [Boost-users] [enable_shared_from_this] My derivation ofenable_shared_from_this wants to be templated

Subject: Re: [Boost-users] [enable_shared_from_this] My derivation ofenable_shared_from_this wants to be templated
From: Peter Dimov (pdimov_at_[hidden])
Date: 2009-03-04 15:03:31

Rob Currey:
> template<class X>
> class Y: public enable_shared_from_this< Y<X> >
> {
> public:
> 
>     shared_ptr< Y<X> > f()
>     {
>         return shared_from_this();

In a template, you need

           return this->shared_from_this();

to inform the compiler that shared_from_this will come from a base class.

>     }
> };