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Subject: Re: [Boost-users] [TypeTraits] Is it possible to detect that type is not exist and use default type?
From: Sakharuk, Vlad \(GMI Development\) (Vlad_Sakharuk_at_[hidden])
Date: 2009-06-30 15:53:14


Thanks!

-----Original Message-----
From: boost-users-bounces_at_[hidden]
[mailto:boost-users-bounces_at_[hidden]] On Behalf Of Steven
Watanabe
Sent: Tuesday, June 30, 2009 3:40 PM
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] [TypeTraits] Is it possible to detect that
type is not exist and use default type?

AMDG

Sakharuk, Vlad (GMI Development) wrote:
> Here is example:
> class one {
> public:
> typedef someclass internal;
> };
>
> class two {
> // No internal class
> };
>
> class default_internal{
> };
>
> I would like to be able to write something if it possible:
>
> template<class T, class B = if_exist(T::internal) T::internal else
> default_internal > class proc { };
>
> So I can use proc with both
>
> proc<one> One;
> proc<two> Two;
>
> without specifying derived type?

Use BOOST_MPL_HAS_XXX_TRAIT_DEF with boost::mpl::eval_if.

#include <boost/mpl/has_xxx.hpp>
#include <boost/mpl/eval_if.hpp>

BOOST_MPL_HAX_XXX_TRAIT_DEF(internal)

template<class T>
struct get_internal {
    typedef typename T::internal type;
};

template<
    class T,
    class B = typename boost::mpl::eval_if<has_internal<T>,
        get_internal<T>,
        boost::mpl::identity<default_internal>
>::type
>
class proc;

In Christ,
Steven Watanabe

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