Re: [Boost-users] A question on member functions in a class using lambda expression? Can anyone with kindness help me?

Subject: Re: [Boost-users] A question on member functions in a class using lambda expression? Can anyone with kindness help me?
From: fmingu (fmingu_at_[hidden])
Date: 2009-07-21 03:56:35

Oh.Please do not play joke on me.
I am doing my work seriously. I really want the answer on lambda expression in order to know lambda expression further.
Can any one with kindness help me?

I am using Dev-C++ 4.9.8.0,with lambda expression: 
..................... 
class A{ 
............ 
int result; 
double function2(const int& n) 
........................ 
double function3(const int& Q,const int& N) 
..................... 
double function1(const int& q, int& n){ 
    double result=0.0; 
    int loopvalue=0, totaltime=n; 
    n%=q; 
    ++thenumbern; 
   ( for_loop(var(loopvalue)=0,var(loopvalue)<=var(totaltime),++var(loopvalue), 
        var(result)+=( bind(&A::function2,_2)*bind(&A::function3,_1,_2))))(q,n); 
    return result; 
} 
But the complier told me that: 
.............................. 
\boost\lambda\detail\select_functions.hpp 
  instantiated from `Arg::sig<boost::tuples::tuple<A&,................. 
instantiated from `RET boost::lambda::lambda_functor_base<boost::lambda::forloop_action, Args>::call(A&, B&, C.................... 
\boost\lambda\detail\lambda_functors.hpp 
  instantiated from `T::sig<boost::tuples::tuple<A&, B&, boost::tuples::null_type, boost::tuples::null_type, ............... instantiated from here 

By the way, is the result in var(result) the double result in function1 or the int result in class A? 
Can any one with kindness help me?