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Boost Users : |
Subject: Re: [Boost-users] [python] Passing pointers as arguments without copying.
From: Germán Diago (germandiago_at_[hidden])
Date: 2009-09-26 04:38:51
>I don't know about the whole boost::noncopyable, but if you dont want
>to pass a copy of the class, doesn't a reference/pointer do th trick?
I don't know how to do it.
I mean, I try to expose the class
class_ <MyClass2, boost::noncopyable>...;
class_<MyClass, boost::noncopyable>("MyClass", ...).
def(&MyClass::f, "f");
The problem is that "f", exposed to python, takes an argument of type
MyClass2 *.
But MyClass2 * is noncopyable. So I cannot expose f that way because
python will try to copy *myclass2 and it's noncopyable.
How can I avoid that copying? I don't know how. I saw something with ptr(),
but it was to take a function with parameters from python to c++, not
the other way, which
is what I'm trying.
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