Re: [Boost-users] [Thread] join_all and interrupt_all playing together

Subject: Re: [Boost-users] [Thread] join_all and interrupt_all playing together
From: Anthony Williams (anthony.ajw_at_[hidden])
Date: 2009-10-22 03:59:34

Ryan McConnehey <mccorywork_at_[hidden]> writes:

> I'm trying to set several threads running and have the main thread
> signal an interrupt.  I've included an example that shows what I'm
> trying to accomplish.  The threads that are created are associated
> with thread_group and then a join_all is called.  I would expect the
> main thread to be able to call interrupt_all on the thread_group.
> Since this wasn't working I looked at what the join_all and
> interrupt_all function were actually doing.  It turns out that
> thread_group has a mutex that is being called for each function and
> since the mutex for join_all is in use, the lock in interrupt_all is
> blocking.  I understand why the mutex is there but am unclear how
> interrupt_all is suppose to work with join_all.  To accomplish the
> functionality I need I have to use create_thread and store the return
> pointer in a list of my own.  Then call interrupt on each pointer I
> stored.  Which is basically duplicating the storage of thread_group.
> This seem like a waste.  I would appreciate any advice.

There's an open trac issue about it. I'm working on boost::thread today,
so I'll apply the patch.

Anthony
-- 
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