Re: [Boost-users] concat integer to wstring

Subject: Re: [Boost-users] concat integer to wstring
From: Chris Johnson (plasticchris_at_[hidden])
Date: 2009-11-14 02:41:36

Or use stringstreams (which is, I believe, how lexical_cast is implemented).

It should look something like this:

std::wstringstream oss;
std::wstring mystr;

std::wstring ws=L"str";

for(int i=0;i<10;++i)
{
 oss << ws << i;
}

mystr=oss.str();

std::cout << mystr;

On 11/12/09, Lloyd <lloyd_at_[hidden]> wrote:
> Thanks, it works...
>
> On Fri, 13 Nov 2009 01:05:44 +0530, Steven Watanabe <watanabesj_at_[hidden]>
> wrote:
>
>> AMDG
>>
>> Lloyd wrote:
>>> What is the best way to concatanate an integer to wstring?
>>>
>>> for example
>>> ===========
>>>
>>> std::wstring ws=L"str";
>>>
>>> for(int i=0;i<10;++i)
>>> {
>>>  cout<<ws+i;
>>> }
>>>
>>> The output could be
>>> str1
>>> str2
>>> ....
>>> str9
>>
>> ws + boost::lexical_cast<std::wstring>(i)?
>>
>> In Christ,
>> Steven Watanabe
>>
>> _______________________________________________
>> Boost-users mailing list
>> Boost-users_at_[hidden]
>> http://lists.boost.org/mailman/listinfo.cgi/boost-users
>
>
>
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