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Subject: Re: [Boost-users] How to return a Null pointer for shared_ptr
From: Emil Dotchevski (emildotchevski_at_[hidden])
Date: 2009-12-01 20:24:22


Use

return IntPtr();

This will also return NULL if IntPtr is a typedef of a raw pointer type.

Emil Dotchevski
Reverge Studios, Inc.
http://www.revergestudios.com/reblog/index.php?n=ReCode

On Tue, Dec 1, 2009 at 5:12 PM, hce <webmail.hce_at_[hidden]> wrote:
> Hi,
>
> I defined a shared_ptr in to a map table. How can I return a NULL
> pointer in a function to search the table if it is not found as
> following example?
>
> typedef shared_ptr<int> IntPtr;
> typedef std::map<std::string IntPtr> MapTable;
>
> MapTable mt;
>
> IntPtr search(const std::string& key)
> {
>    MapTable::const_iterator it = mt.find(key);
>    if (it == mt.end()) {
>         return NULL; // can't compile it??
>    }
>    return it->second;
> }
>
> Thank you.
>
> Kind regards,
>
> Jupiter
> _______________________________________________
> Boost-users mailing list
> Boost-users_at_[hidden]
> http://lists.boost.org/mailman/listinfo.cgi/boost-users


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