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Subject: Re: [Boost-users] condition_variable
From: Adam Szeliga (aszeliga.xsoftware_at_[hidden])
Date: 2009-12-10 17:11:08
This is scheme which I often use:
// Common for both threads
boost::mutex mutex;
boost::condition condition;
// Thread1:
boost::xtime waitingTime(set value of waiting time)
{
boost::mutex::scoped_lock lock(mutex)
do
{
if (some_event occurred)
{
do something after received event
return; // exit point after receive event
}
} while (condition.timed_wait(lock, waitingTime));
do something after timeout occurred // exit point after timeout
}
//Thread2
{
boost::mutex::scoped_lock lock(mutex);
set some event which is been waiting thread1
condition.notify_one();
}
Maybe will be useful for you.
Adam
Nikolai N Fetissov wrote:
>> Thanks Nikolai,
>> That explains why the second thread can lock that mutex. From what you are
>> saying then, the sleeping thread will wake up and reacquire the lock after
>> notify is called. So the thread that calls notify should not hold that
>> lock
>> when this happens or you could have deadlock right?.
>>
>>
>
> Alessandro,
>
> The thread calling the 'notify' can, but does not have to, hold
> a mutex at the time. In theory all the notify() function does is
> mark the thread sleeping on the condition as runnable. There's
> no deadlock here. Also google for 'spurious wakeup' to get a firm
> hold on mutex/cv concepts.
>
> Cheers,
> --
> Nikolai
>
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