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Subject: Re: [Boost-users] Detect specialized template function?
From: Andrew Chinkoff (achinkoff_at_[hidden])
Date: 2010-01-29 07:34:30


Hi, Daniel.

Daniel wrote:
> For example, the mere existance of the specialization
> template <> void S<int>::g() { ... }
> should trigger special logic in S<int>::f().

Couldn't you explain what "trigger special logic" means?
Specializing template for concrete type we trigger special logic, don't we?

Best,
Andrew

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