Re: [Boost-users] [mpl - function_types] Generate typedef from operator() of a functor

Subject: Re: [Boost-users] [mpl - function_types] Generate typedef from operator() of a functor
From: Olivier Tournaire (olitour_at_[hidden])
Date: 2010-01-30 10:39:45

Thanks again Joel.

2010/1/30 joel falcou <joel.falcou_at_[hidden]>

> Olivier Tournaire wrote:
>
>> Hi all,
>>
>> Given an mpl sequence of types such as: typedef mpl::vector<T0, T1, T2,
>> T3> arg_types;
>>
>> 1) the users of my library provide functors such as F (where T0 and T1 may
>> have been any of the types of arg_types:
>>
>> class F {
>>  typedef mpl::pair<T0,T1> signature_type;
>>  double operator()(const T0& t0, T1& t1);
>> };
>> is there a way to generate signature_type automatically ?
>>
>>  Retrieve the operator() params usign aprameter_types, it'll end up as
>
> vector<F*,T0,T1>
>
> then use mpl::pop_front to remove the unwanted pointer to member
>
>
>  2) if the operator() is overloaded, the user class currently has to
>> typedef an mpl::vector of mpl::pairs such as
>>
>> class G {
>>  typedef mpl::vector<mpl::pair<T2,T3>, mpl::pair<T1,T1>, mpl::pair<T3,T1>
>> > signature_type;
>>  double operator()(const T2& t2, T3& t3);
>>  double operator()(const T1& t1, T1& t1);
>>  double operator()(const T3& t3, T1& t1);
>> };
>>
>>  Why don't you use something like the result_of protocol ?
>

Why not. Could you give us more details ?

Regards

> Maybe easier
>
> --
> ___________________________________________
> Joel Falcou - Assistant Professor
> PARALL Team - LRI - Universite Paris Sud XI
> Tel : [phone]
>
>
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