Re: [Boost-users] [Function] Overloaded functor as a boost::function

Subject: Re: [Boost-users] [Function] Overloaded functor as a boost::function
From: Alexander Lamaison (awl03_at_[hidden])
Date: 2010-02-13 20:40:52

On Sun, 14 Feb 2010 01:11:21 +0000, Alexander Lamaison wrote:

> I'm trying to pass a function with an overloaded operator() to a function
> expecting a boost::function parameter.  This fails to compile as it appears
> to pick the wrong overload.

My bad.  I was using a subclass of the functor and name hiding came into
play.  A 'using' declaration fixed this.

Thanks

Alex