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Subject: Re: [Boost-users] [Lambda] Lost in lambda land!
From: Ovanes Markarian (om_boost_at_[hidden])
Date: 2010-03-24 05:19:43
On Wed, Mar 24, 2010 at 9:38 AM, Robert Jones <robertgbjones_at_[hidden]>wrote:
>
> It does indeed, making method f() const fixes it, but I still can't quite
> see why. Without the
> constness of f() the guts of the error says this,
>
> /usr/include/boost/lambda/detail/actions.hpp:87: error: no matching
> function for call to boost::lambda::function_adaptor<void
> (A::*)()>::apply(void (A::* const&)(), const A&)
>
> from which it seems that the constructed required signature includes a
> const A&. Why is this?
>
Because A() is an rvalue, a temporary which cannot be assigned to a
non-const reference.
What you propose is pretty equal to the following ill-formed construct:
void do_smth(A& a)
{
// do smth.
}
do_smth(A(7));
So the best boost::bind overload which compiler finds is that which accepts
A const& => only const members are allowed to be accessed.
Regards,
Ovanes
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