Re: [Boost-users] phoenix function problem

Subject: Re: [Boost-users] phoenix function problem
From: Joel de Guzman (joel_at_[hidden])
Date: 2010-04-23 19:41:31

On 4/23/2010 2:58 PM, Olaf Peter wrote:

>> Your operator()s are wrong (C++ error, unrelated to phoenix).
>> Try this:
>>
>> #if WANT_TO_HAVE
>>      template<typename T, typename ID>
>>      struct result { typedef vector_type type; };
>>
>>      vector_type operator()( const vector_type&  v, rlc ) const
>>      {
>>          return fusion::as_nview<0, 1, 2>( v );
>>      }
>>
>>      vector_type operator()( const vector_type&  v, lcr ) const
>>      {
>>          return fusion::as_nview<2, 0, 1>( v );
>>      }
>>
>> #else
>
> This fails to compile as well:

Olaf, I recommended writing the code above (see the operator() is
*not* a template. Why do you still insist on writing it as a
template? Here is your problem:

     template <typename T>
     vector_type operator()( const vector_type& v, rlc ) const
     {
         return fusion::as_nview<0, 1, 2>( v );
     }

     template <typename T>
     vector_type operator()( const vector_type& v, lcr ) const
     {
         return fusion::as_nview<2, 0, 1>( v );
     }

because you don't have any arguments with T.

Regards
-- 
Joel de Guzman
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