Re: [Boost-users] enable-if overloading out the wazoo

Subject: Re: [Boost-users] enable-if overloading out the wazoo
From: John Dlugosz (JDlugosz_at_[hidden])
Date: 2010-04-26 19:31:10

> -----Original Message-----
> From: boost-users-bounces_at_[hidden] [mailto:boost-users-
> bounces_at_[hidden]] On Behalf Of vicente.botet
> Sent: Monday, April 26, 2010 1:26 AM
> To: boost-users_at_[hidden]
> Subject: Re: [Boost-users] enable-if overloading out the wazoo
> 
> ----- Original Message -----
> From: "John Dlugosz" <JDlugosz_at_[hidden]>
> To: <boost-users_at_[hidden]>
> Sent: Friday, April 23, 2010 10:31 PM
> Subject: [Boost-users] enable-if overloading out the wazoo
> 
> 
> >
> > I tried something like this:  First, the general form in one header
> known by everything:
> >
> >  template <typename T1, typename T2>
> >  dim_s foo (const T1& left, const T2& right);
> >
> > Then, in a header that gets more concrete, provide its own form that
> is meant to be used when objects of those types are involved:
> >
> >   template<typename T1, typename T2>
> >   typename enable_if_c<
> >      is_base_of<genericbase,T1>::value &&
> >      is_base_of<genericbase,T2>::value,
> >   dim_s>::type foo (const T1& left, const T2& right);
> >
> 
> What about overloading with the genericbase class?
> 
> dim_s foo (const genericbase& left, const genericbase& right);
> 
> Am I missing something?
> 
> Best,
> Vicente


The plain overloaded function will be a worse match than the first template form I showed, which is always an exact match for all types.  It won't get used.

--John







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