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Subject: [Boost-users] [Random] uniform_int::operator()(Engine &, result_type)
From: Hossein Haeri (powerprogman_at_[hidden])
Date: 2010-07-19 14:20:22

Dear all,

I was looking at the uniform_int<>'s reference page:

and realised that there is no information whatsoever about what the following overload of its operator () does:

template<typename Engine>
result_type operator()(Engine & eng, result_type n) ;

Do I understand it correctly that this generates a number in [min, n] (probably subject to some good conditions)?


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