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Subject: Re: [Boost-users] BoostSerialization callinga customserialize method
From: Pooyan Dadvand (pooyan_at_[hidden])
Date: 2010-08-27 13:33:11
_______________________________________________________________________________________________________________________________________________________________________________
Dr. Pooyan Dadvand
International Center for Numerical Methods in Engineering - CIMNE
Campus Norte, Edificio C1
c/ Gran Capitán s/n
08034 Barcelona, Spain
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On 08/27/2010 07:55 PM, Robert Ramey wrote:
> Pooyan Dadvand wrote:
>
>> Do you know any boost tool to get the pointer to the derive class
>> like this:
>>
>>
>> template<class TArchiveType>
>> MyContainer::serialize(TArchiveType&rArchive, const unsigned int
>> Version)
>> {
>>
>> boost_tool_to_get_drived_class_pointer(p_variable_data)->MyCustomSerialize(rArchive,
>> Version, MyData);
>> }
>>
> I'm not going to tell you how to do this because doing this won't help you !
>
> Reread the section of the documentation which addresses serialization of
> pointers. It
> discusses the serialization of an object through a pointer to the virtual
> base class
>
I have already read it!
> so all you have to do is
>
> base_class *m_bc; // where base class is a virtual base class.
>
>
> ar<< m_dc
>
I'm already using this for serializing a derived class and it works
fine, but it's not the case here.
> The serialization library keeps track of the "true" (most derived) class and
> call the serialize
> function on THAT class. You don't have to do anything to get what you want.
>
It keep track of "serialize" method with two parameters and I need an
additional parameter!
> I would
> suggest you look through the tests/examples (there are 50+ in the library!)
> and find
> one that does this and study it.
>
>
>
>
>> Or tell me how the following code in oserializer.hpp can be used for
>> my case
>>
> <snip>
>
> the above example ar<< m_dc will in fact use that code.
>
> One time we had a similar thread. The final result was
>
> "Oh - this is really simple - once you see it!"
>
> So if what you want to do is NOT simple, you're doing it wrong.
>
Of course I'm doing something wrong, for this reason I'm asking the
correct way. however I don't see an easy solution to my problem looking
to the examples for the very standard cases.
> Start make taking one of your types
> serialize it
> make a small test to prove that it works.
>
I have already done this.
> Add the next higher type
> and repeat
>
Exactly the methodology I'm using.
> make a test which does the above through a pointer
> and repeat
>
I have already done this and it works.
> add a virtual base class
> and repeat
>
I have already serialized several classes in my library with pointer to
the base classes and they are working.
But it's not what I'm asking. What I'm asking is a very special case in
which the serialize don't have enough information to deal with my void*
in std::pair<VariableData*, void*> and for this reason I need the help
of VariableData derived class to give the serialization the necessary
type information. Actually I get the following error using the normal
serialization method as you suggest:
/usr/local/include/boost/archive/detail/oserializer.hpp:465: error:
'void*' is not a pointer-to-object type
> Robert Ramey
>
>
>
> _______________________________________________
> Boost-users mailing list
> Boost-users_at_[hidden]
> http://lists.boost.org/mailman/listinfo.cgi/boost-users
>
>
Thanks,
Pooyan.
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