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Subject: [Boost-users] fusion transform_view
From: Hicham Mouline (hicham_at_[hidden])
Date: 2010-09-12 06:43:00


Hello

 

After I invoke the

 

result_of::transform<Seq, UnaryFct>

 

metafunction, the result type I get, printed out by typeid(...).name() gives

 

transform_view< Seq, UnaryFct, void_ >

 

is there a way to print out the actual resulting type, forcing the view to
"evaluate" ?

 

regards,



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