Re: [Boost-users] [array][bind] Binding boost array to a boost function

Subject: Re: [Boost-users] [array][bind] Binding boost array to a boost function
From: OvermindDL1 (overminddl1_at_[hidden])
Date: 2010-10-11 18:24:41

On Mon, Oct 11, 2010 at 1:55 PM, michi7x7 <mailing-lists_at_[hidden]> wrote:
> Â Am 11.10.2010 21:46, schrieb Ryan McConnehey:
>>
>> michi7x7 wrote:
>>>
>>> Â Am 11.10.2010 01:59, schrieb Ryan McConnehey:
>>> Hi,
>>>
>>> yes it is, but you need to pass the template-parameters:
>>>
>>> Sorter<int, 8> shell(boost::bind(quicksort<int, 8>, _1));
>>>
>>> or simply
>>>
>>> Sorter<int, 8> shell(quicksort<int,8>);
>>>
>>> Regards,
>>>
>>> michi7x7
>>
>> By binding to the exact template parameters it makes the Sorter not as
>> flexible as I'm hoping. Â If I have two boost arrays defined like so.
>>
>> boost::array<int, 100> Â  base10power2;
>> boost::array<int, 1000> base10power3;
>>
>> Is there a way to just bind the array type but not the size. Â This would
>> let me call the same method with different size arrays.
>>
> Hi,
>
> unfortunately not with boost::array, because the array-size is static. Use
> std::vector instead ;)

No, he can do it, but not with Boost.Bind that I know of, use
Boost.Phoenix instead, it can do this easily (reference
Boost.Phoenix.Function wrapper).

Actually, he might be able to do it with Boost.Bind if he wraps it in
a functor with an operator() that calls his template function...