Re: [Boost-users] [Fusion] functor fused and unfused at the same time

Subject: Re: [Boost-users] [Fusion] functor fused and unfused at the same time
From: alfC (alfredo.correa_at_[hidden])
Date: 2010-11-09 09:03:36

> I then tried this
>
> struct F_impl{
>         typedef result_of::make_map<
>                 p     , q     ,
>                 double, double
>         >::type mapped_arguments;
>         template<class Args> struct result{ typedef double type; };
>         double operator()(mapped_arguments const& args) const{
>                 return at_key<p>(args) + at_key<q>(args);
>         }
>
> };
>
> struct F : F_impl, unfused<F_impl const&>{
>         F() : unfused<F_impl const&>((F_impl const&)*this){}
>         F(F_impl const& f) : F_impl(f), unfused<F_impl const&>((F_impl
> const&)*this){}
>         template<class Args> struct result{ typedef typename
> F_impl::result<Args>::type type; };
>         using F_impl::operator();
>
> };
>
> which seems to work but looks and feels awkward.

Sorry, take that back this second option doesn't work either.
(So, I don't have a single solution for this).

Thank you,
Alfredo