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Subject: [Boost-users] [Regex] Search Substring with paranthesis
From: Subhash Nagre (snagre.mumbai_at_[hidden])
Date: 2011-03-15 08:57:23
Hello,
I have a string "(123) Hello" and I want to seach String (123) using
boost::regex,
Also I needed to do a full word search, so I added \b in the end.
Here is my code
std::string searchWord = "(123)";
searchWord += "\\" + "b"; // Step 1
boost::regex expression;
expression.assign(searchWord);
std::string completeStr = "(123) Hello (123)";
std::string::const_iterator start = completeStr.begin();
std::string::const_iterator end = completeStr.end();
boost::smatch what;
while (boost::regex_search(start, end, what, expression))
{
int32 foundPos = what.position();
int32 foundLen = what.length();
std::string foundString(start + foundPos, start + foundPos + foundLen);
//This foundStr is 123, beacuse it finds a metacharacter in the seach
expression
// Perform some task with foundString
start += foundPos + foundLen;
}
How Can I get (123) back and foundPos and foundLen as 0 and 5 respetively. I
tried creating my search expression as /(123/), but it didn't worked.
Also if I don't add \b in the search expression in Step 1, even in that
case the foundStr is 123 but in that case, the match will be true even for
(1234), which I don't want. I want to find full words only.
Is there is any flag in boost::regex which can help me out or how can I
perform my task.
Thanks in advance
Subhash
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