[Boost-users] help on build and write pointer to socket in raw mode

Subject: [Boost-users] help on build and write pointer to socket in raw mode
From: boost_at_[hidden]
Date: 2011-04-12 12:57:54

On Mon, 11 Apr 2011 22:06:01 -0700 (PDT), Jerry  wrote:
 Thanks Robert.
You mis-understood my intention. What we want is to serilaize an derived
type object directly (not throught base type pointer) but deserialize it to
a base type pointer. So we want the exactly the following codes:   Derived
d; 
oa > b; Â  But it seems this does not work. The reason we prefer this is
that we have three nodes. One node sends/serialize the derived type object,
while two other nodes are receivers. Howerver, one receives/deserializes
the obj via derived type and the other deserializes the obj via base type
pointer. We want, Â  // The sender  Derived d; 
oa > b; Â   //Â The
other Receiver  Derived dcopy; ia >> dcopy;       On Tue, Apr 12, 2011 at
2:14 PM, Robert Ramey [via Boost]  wrote:
 Jerry wrote: 
> I know that we
can serialize/deserialize a derived type through a 
> base type pointer
(using register_type()). But I cannot serialize a 
 > derived type and
deserialize it through a base type pointer. It seems 
> to me the data type
in serialization and deserialization should be 
> extactly the same one.

when you serialize through a derived type, extra information 
 about the
derived type isn't saved as it's assumed it will 
be deserialized the same
way. 

> 
> What I want is, 
> 
> Base{...}; 
> Derived : Base{...}; 
> 
>
//Derived d; 
 Base *d = new Derived; // use this instead !! 

>
boost::archive::binary_oarchive oa(...); 
> oa  
> Base *b; 
>
boost::archive::binary_iarchive ia(...); 
> ia.register_type(); 
 > ia >> b
 // Deseiralize to a base type pointer 
> 
> I have tried this but it does
not work. Is there any way to make this 
> work? 
> 
> Many thanks!!!

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