Re: [Boost-users] multi-array and pdes

Subject: Re: [Boost-users] multi-array and pdes
From: petros (pmamales_at_[hidden])
Date: 2011-05-22 11:53:15

Hi Larry,
apologies, for not being clear.
Yes, MA is boost::multi_array. M, N, L are the dimensions
(this is only a "logical" statement, rather than a proper code snippet).
I think I have pretty much sorted out the calling practices wrt multi-aray 
and looking
for if certain functionality exists.
My problem amounts to having a view that would allow for the permutation
(if not rotation) of axes.
As I begun to explain, the operator splitting methods decompose a problem in 
N dimensions
into N 1-dimensional problems.
The problem itself is stated, though, in a certain reference system (this 
means that the discretized
operators (stencils) and the boundary conditions are expressed in terms of 
these boundary conditions.
However, the linear equation systems that are produced, are in tridiagonal 
form, only in one of these steps
( the first step of the 1-D problems ). Otherwise it produces a block-banded 
system of equations, that can
be reduced back to the familiar tridiagonal ( conceptually), through axes 
permutation (or rotation).
If one things in terms of the 2D problem analog, while conceptually it would 
amount to exchange the two axes,
in matrix form, and because of the storage alignment it would involve a much 
bigger operation. Since, these
operators/systems are created from the problem, it would be very nice to 
have this view functionality to exploit
for keeping the storage of the operators in the desired form.

I hope this is clearer now - don't mean to drag you into my problem.
Thank you for your response,
Petros

-----Original Message----- 
From: Larry Evans
Sent: Sunday, May 22, 2011 10:43 AM
To: boost-users_at_[hidden]
Subject: Re: [Boost-users] multi-array and pdes

On 05/21/11 15:02, petros wrote:
Hi Petros,

[snip]
> Suppose then that I have a MA( M, N, L ):

Please be more specific.  I assume:

  MA means boost::multi_array

however, I've no idea what M, N, and L are.  Could you please
explain further?

-regards,
Larry

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